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| Analog J and S | l data field |
l - {[(DesiredD - Z) / (F - Z)] * 4095} Convert to 3 hex digits
| Where: | |
| l is the 3 hex digit value to be entered into the instruction
DesiredD is the actual value desired in decimal based on the module units. For example, if you want a module to read 2.5 Volts, then DesiredD = 2.5. F is the full scale value of the module and Z is the zero scale of the module. These are shown for the standard modules in the table below. |
| duTec Module | F | Z | Units |
|---|---|---|---|
| OV5 | 5 |
0 |
Volts |
| OV10 | 10 |
0 |
Volts |
| OI420 | 20 |
4 |
mAmps |
| Example: | 3.6 Volts output by an OV10 Module |
| l = [(3.6 - 0) / (10 - 0)] * 4095 | |
| = 0.36 * 4095 | |
| = 1474.2 | |
| = 5C2H is the value entered in the l data field |
| Analog K | l data field |
ResponseD = [(l / 4095) * (F - Z) + Z]
| Where: | |
| Response is actual value read by the input in engineering units.
l is the 3 digit hex value converted to decimal. F is the full scale value of the module, and Z is the zero scale of the module. These are shown for the standard modules in the table below. |
| duTec Module | F | Z | Units |
|---|---|---|---|
| OV5 | 5 |
0 |
Volts |
| OV10 | 10 |
0 |
Volts |
| OI420 | 20 |
4 |
mAmps |
| Example: | 78FH is returned from an OI420 Module 78FH = 1935D |
||
| ResponseD | = (1935 / 4095) * (20 - 4) + 4 | ||
| = 0.473 * 16 + 4 | |||
| = 7.56 + 4 | |||
| = 11.56 mA | |||
| Analog V | p and q data field |
p or q = [(DesiredD - Z) / (F - Z)] * 4095 Convert to 3 hex digits
| Where: | |
| p or q is the 3 hex digit value entered into the instruction.
DesiredD is the amplitude desired in engineering units. F is the full scale value of the module and Z is the zero scale of the module. These are shown for the standard modules in the table below. |
| duTec Module | F | Z | Units |
|---|---|---|---|
| OV5 | 5 |
0 |
Volts |
| OV10 | 10 |
0 |
Volts |
| OI420 | 20 |
4 |
mAmps |
| Example: | 18mA is the desired maximum amplitude and 7 is the desired minimum amplitude for an OI420 (4-20mA) Module |
| p = [(18 - 4) / (20 - 4)] * 4095 | |
| = {14 / 16} * 4095 | |
| = 0.875 * 4095 | |
| = 3583.125 = DFFH | |
| q = [(7 - 4) / (20 - 4)] * 4095 | |
| = [3 / 16] * 4095 | |
| = 0.1875 * 4095 | |
| = 767.81 = 2FFH | |
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