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I/O PLEXER Hardware ManualAppendices |
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Figure A-1 (below) shows the equivalent RS-422/485 communication circuit for the I/O PLEXER. When switched to "Last Station" the 150 ohm network terminator resistors are in place.
Positions A-D of SW2 allow the removal/installation of network biasing resistors used to suppress line noise when all transmitters are at rest. These resistors should be left active on at least one, but not more than eight units in a single multidrop network segment. If more than eight resistor equipped units are present, transmitter overloading may occur.
Figure A-1 Electrical Equivalent Circuit
The I/O PLEXER samples individual analog inputs at the constant rate of 100 samples per second. The effective sample rate per channel is determined by the total number of channels to be sampled.
Input data throughput is based on the time from the beginning of the first character of an instruction to the end of the last character of the response. The processing time of the host computer controlling input instructions will reduce the effective throughput.
Outout execution throughput is based on the time from the beginning of the first character of an instruction to the time when the actual output changes. Because the instruction acknowledgement response occurs before outputs actually change state, the processing time of the host computer controlling output instructions can reduce the effective throughput.
The tables below show msec per channel and channels per second for 1 and 16 I/O channel cases.
Baud Rate |
Output (Digital J) |
Input (Digital M) |
||||||
---|---|---|---|---|---|---|---|---|
1 Channel/IOP |
16 Channels/IOP |
1 Channel/IOP |
16 Channels/IOP |
|||||
mSec/ |
Chan/ |
mSec/ |
Chan/ |
mSec/ |
Chan/ |
mSec/ |
Chan/ |
|
300 |
501 |
2 |
501 |
32 |
379 |
3 |
379 |
42 |
600 |
251 |
4 |
251 |
64 |
195 |
5 |
195 |
82 |
1200 |
126 |
8 |
126 |
127 |
104 |
10 |
104 |
154 |
2400 |
64 |
16 |
64 |
252 |
58 |
17 |
58 |
277 |
4800 |
32 |
31 |
32 |
496 |
35 |
29 |
35 |
458 |
9600 |
17 |
60 |
17 |
962 |
23 |
43 |
23 |
682 |
19200 |
9 |
113 |
9 |
1816 |
18 |
56 |
18 |
902 |
38400 |
5 |
203 |
5 |
3261 |
15 |
67 |
15 |
1076 |
Baud Rate |
Input (Analog L) |
Output (Analog S) |
||||||
---|---|---|---|---|---|---|---|---|
1 Channel/IOP |
16 Channels/IOP |
1 Channel |
16 Channel |
|||||
mSec/ |
Chan/ |
mSec/ |
Chan/ |
mSec/ |
Chan/ |
mSec/ |
Chan/ |
|
300 |
639 |
2 |
2639 |
6 |
484 |
2 |
1984 |
8 |
600 |
323 |
3 |
1323 |
12 |
250 |
4 |
1000 |
16 |
1200 |
164 |
6 |
664 |
24 |
134 |
7 |
509 |
31 |
2400 |
85 |
12 |
335 |
48 |
75 |
13 |
263 |
61 |
4800 |
46 |
22 |
171 |
94 |
46 |
22 |
140 |
114 |
9600 |
26 |
39 |
88 |
181 |
32 |
32 |
78 |
204 |
19200 |
16 |
63 |
47 |
339 |
24 |
41 |
48 |
335 |
38400 |
11 |
91 |
27 |
602 |
21 |
48 |
32 |
494 |
The equations below can be used for determining mSec for any number of channels.
Throughput for digital I/O is independent of the number of channels.
DIRate = (( |
(15Characters * 10Bits) BaudRate |
) + 0.001mS ) * 1000mS |
Figure B-1 Digital Input Data Time for 1-16 channels
DORate = (( |
(11Characters * 10Bits) BaudRate |
) + 0.012mS ) * 1000mS |
Figure B-2 Digital Output Execution 1-16 channels
Throughput for analog I/O varies with the number of channels, n.
AIRate = (( |
((15Characters + ( 4 Characters* NChannels)) * 10Bits) BaudRate |
) + 0.006mS ) * 1000mS |
Figure B-3 Analog Input Data Time for n channels.
AORate = (( |
((11Characters + ( 3 Characters*
NChannels))
* 10Bits) BaudRate |
) + 0.017mS ) * 1000mS |
Figure B-4 Analog Output Execution n channels.
The throughput for systems with a mixture of analog and digital data is determined by the sum of the time for each instruction using these equations.
Appendix C is the Protocol Instruction Set, which may be found here.
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